# Line slope calculator 3x+y=23

**Straight line given by points A[5; 8] and B[6; 5]**

## Calculation:

**Slope-intercept form of line:**y = -3x+23

**Canonical form of the line equation:**3x+y-23 = 0

**Parametric form of the line equation:**

x = t+5

y = -3t+8 ; t ∈ R

**Slope:**m = -3

**Slope angle of line: φ =**-71°33'54″ = -1.249 rad

**X intercept:**x

_{0}= 7.6667

**Y intercept:**y

_{0}= q = 23

**Distance line from the origin:**d

_{0}= 7.2732

**The length of the segment AB: |AB| =**3.1623

**Vector: AB =**(1; -3)

**Normal vector: n =**(3; 1)

**Midpoint of the segment AB: M =**[5.5; 6.5]

**Perpendicular Bisector equation:**x-3y+14 = 0

**Vector OA = (5; 8) ; |OA| = 9.434**

**Vector OB = (6; 5) ; |OB| = 7.8102**

**Scalar product OA .OB = 70**

**Angle ∠ AOB = 18°11'21″ = 0.3175 rad**