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5:53

A point `O` inside a rectangle `A B C D` is joined to the vertices. Prove that the sum of the areas of a pair of opposite triangles so formed is equal to the sum of the other pair of triangles. Given: A rectangle `A B C D\ a n d\ O` is a point inside it. `O A ,\ O B ,\ O C\ a n d\ O D` have been joined. To Prove: `a r\ (A O D)+\ a r\ ( B O C)=\ a r\ ( A O B)+\ a r( C O D)`

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5:42

A point `O` inside a rectangle `A B C D` is joined to the vertices. Prove that the sum of the areas of a pair of opposite triangles so formed is equal to the sum of the other pair of triangles. Given: A rectangle `A B C D\ a n d\ O` is a point inside it. `O A ,\ O B ,\ O C\ a n d\ O D` have been joined. To Prove: `a r\ (A O D)+\ a r\ ( B O C)=\ a r\ ( A O B)+\ a r( C O D)`

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4:29

A point `O` inside a rectangle `A B C D` is joined to the vertices. Prove that the sum of the areas of a pair of opposite triangles so formed is equal to the sum of the other pair of triangles. GIVEN : A rectangle `A B C D` and `O` is a point inside it. `O A ,O B ,O C` and `O D` have been joined.. TO PROVE : `a r(A O D)+a r( B O C)=a r( A O B)+a r( C O D)` CONSTRUCTION : Draw `E O F A B` and `L O M A Ddot`

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2:10

`A B C D` IS A PARALLELOGRAM AND `O` is any point in its interior. Prove that: `a r ( A O B)+ a r ( C O D)= a r ( B O C)+ a r( A O D)` `a r ( A O B)+a r (C O D)=1/2 a r(^(gm)A B C D)` Given: A parallelogram `A B C D a n d O` is a point in its interior. To Prove: `a r ( A O B)+ a r( C O D)=a r ( B O C)+a r( A O D)`

95.9 K+ Views | 4.7 K+ Likes