Shared Flashcard Set

Details

Lab 1
Acceleration of Falling Objects
12
Physics
Undergraduate 2
08/27/2012

Additional Physics Flashcards

 


 

Cards

Term
gravity=
Definition
9.8m/s2
Term
acceleration=
Definition

v


t

 

=

 

v2-v1


t

Term
velocity=
Definition

d


t

Term
Name the 5 steps for standard deviation.
Definition

1. subract the mean from each data point

2. square your answers

3. add all answers together

4. take sum and divide by # of sample

5. take quotent and find √x

Term

Fill in the blanks for the following example of Standard Deviation:

 

Mean of 10,12=_____

10-____=-1__=____

12-____=1__=____

___+____=2

2/____=1

√___=1

 

Definition

11

11  2   1

11   2   1

1   1

2

1

Term
What is standard deviation used for?
Definition
It gives a measure of the percision of a method.
Term

Class average acceleration=9.6m/s/s±0.4m/s/s

Express this as a percentage of the value for the acceleration.

Definition
(0.4/9.6)(100)=4.2%
Term

Class average acceleration=9.6m/s/s±0.4m/s/s

Compare the class average value for the acceleration with the acceleration of gravity.

Definition
(9.6/9.8)(100)=98%
Term

Class average acceleration=9.6m/s/s±0.4m/s/s

Express the experomental error as a percentage of the value for acceleration.

Definition
(ι9.8-9.6ι / 9.8)(100)=2%
Term
In an experiment to measure acceleration of a free falling object that involves using a wire and a spark timer, name three possible factors that might reduce the measured acceleration of the mass from the known acceleration of the gravity.
Definition

-human error

-air resistance

-wire is not straight and can cause object to hit paper

Term

An object is dropped from rest and falls for 3.5 seconds.

Find:

A) the speed of the object

B) the distance the object has fallen

Definition

A) v=gt=(9.8m/s)(3.5s)=34.3m/s/s

therefore the object was traveling at 34.3 meters per second per second

 

B) d=(1/2)gt2=(1/2)(9.8m/s)(3.5s)2=60m

therefore the object fell for 60 meters

Term

A rock is dropped from the top of a 30 m high cliff.

Find:

A) how long it will take to hit the ground

B) the speed as it hits the ground

Definition

A) d=(1/2)gt2

30m=(1/2)(9.8m/s2)t2

√(60m/9.8m/s2)=√t2

2.5s=t

therefore, it will take the rock 2.5 seconds to hit the ground

 

B) v=gt=(9.8m/s2)(2.5s)=24.5m/s

therefore, the rock will be traveling a speed of 24.5 meters per second when it hits the ground

Supporting users have an ad free experience!