# Shared Flashcard Set

## Details

Lab 1
Acceleration of Falling Objects
12
Physics
08/27/2012

Term
 gravity=
Definition
 9.8m/s2
Term
 acceleration=
Definition
 v t   =   v2-v1 t
Term
 velocity=
Definition
 d t
Term
 Name the 5 steps for standard deviation.
Definition
 1. subract the mean from each data point 2. square your answers 3. add all answers together 4. take sum and divide by # of sample 5. take quotent and find √x
Term
 Fill in the blanks for the following example of Standard Deviation:   Mean of 10,12=_____ 10-____=-1__=____ 12-____=1__=____ ___+____=2 2/____=1 √___=1
Definition
 11 11  2   1 11   2   1 1   1 2 1
Term
 What is standard deviation used for?
Definition
 It gives a measure of the percision of a method.
Term
 Class average acceleration=9.6m/s/s±0.4m/s/s Express this as a percentage of the value for the acceleration.
Definition
 (0.4/9.6)(100)=4.2%
Term
 Class average acceleration=9.6m/s/s±0.4m/s/s Compare the class average value for the acceleration with the acceleration of gravity.
Definition
 (9.6/9.8)(100)=98%
Term
 Class average acceleration=9.6m/s/s±0.4m/s/s Express the experomental error as a percentage of the value for acceleration.
Definition
 (ι9.8-9.6ι / 9.8)(100)=2%
Term
 In an experiment to measure acceleration of a free falling object that involves using a wire and a spark timer, name three possible factors that might reduce the measured acceleration of the mass from the known acceleration of the gravity.
Definition
 -human error -air resistance -wire is not straight and can cause object to hit paper
Term
 An object is dropped from rest and falls for 3.5 seconds. Find: A) the speed of the object B) the distance the object has fallen
Definition
 A) v=gt=(9.8m/s)(3.5s)=34.3m/s/s therefore the object was traveling at 34.3 meters per second per second   B) d=(1/2)gt2=(1/2)(9.8m/s)(3.5s)2=60m therefore the object fell for 60 meters
Term
 A rock is dropped from the top of a 30 m high cliff. Find: A) how long it will take to hit the ground B) the speed as it hits the ground
Definition
 A) d=(1/2)gt2 30m=(1/2)(9.8m/s2)t2 √(60m/9.8m/s2)=√t2 2.5s=t therefore, it will take the rock 2.5 seconds to hit the ground   B) v=gt=(9.8m/s2)(2.5s)=24.5m/s therefore, the rock will be traveling a speed of 24.5 meters per second when it hits the ground
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