# Line slope calculator 5x-4y=-5

**Straight line given by points A[3; 5] and B[7; 10]**

## Calculation:

**Slope-intercept form of line:**y = 1.25x+1.25

**Canonical form of the line equation:**5x-4y+5 = 0

**Parametric form of the line equation:**

x = 4t+3

y = 5t+5 ; t ∈ R

**Slope:**m = 1.25

**Slope angle of line: φ =**51°20'25″ = 0.8961 rad

**X intercept:**x

_{0}= -1

**Y intercept:**y

_{0}= q = 1.25

**Distance line from the origin:**d

_{0}= 0.7809

**The length of the segment AB: |AB| =**6.4031

**Vector: AB =**(4; 5)

**Normal vector: n =**(5; -4)

**Midpoint of the segment AB: M =**[5; 7.5]

**Perpendicular Bisector equation:**4x+5y-57.5 = 0

**Vector OA = (3; 5) ; |OA| = 5.831**

**Vector OB = (7; 10) ; |OB| = 12.2066**

**Scalar product OA .OB = 71**

**Angle ∠ AOB = 4°1'42″ = 0.0703 rad**