# Shared Flashcard Set

## Details

Final Exam
Lab Math
53
Science
02/20/2013

Term
 How much agarose is needed in making an 0.8% agarose gel with a final volume of mL?
Definition
Term
 How much agarose is needed in making an 1% agarose gel with a final volume of mL?
Definition
Term
 How much agarose is needed in making an 0.5% agarose gel with a final volume of mL?
Definition
Term
 How much agarose is needed in making an 1.5% agarose gel with a final volume of mL?
Definition
Term
 You want to make a 2% agarose gel. The stock solution in the cabinet is 50X TAE and you want a final concentration of 1X TAE. You need 50 mL to form the gel. You also want to add ethidium bromide to the gel. The stock solution of EtBr is 10mg/ml but you only need 0.5 micograms/ml. Show you math and describe how you make the gel.
Definition
 buffer = 1mL TAE, EtBr = 0.0025mL = 2.5 micro liters, Agarose = 1g agarose procedure: 1. make 1X TAE by adding 1mL of stock 50mL TAE to a cylinder and then add 49mL of DiH2O2. add 1g agarose to flask3. pour in the 50mL 1X TAE and stir 4. heat in microwave at 30 second intervals 5. when solution is clear, it is done 6. when solution has cooled slightly, add 2.5 microliters EtBr7. Mix solution well8. pour into a gel cassette and add comb
Term
 you have a 50X TBE stock solution and you need 50mL of 1X TBE
Definition
 add 1ml of 50X TBE and 49mL of diH2O
Term
 you have a 50X TBE stock solution and you need 50mL of 5X TBE
Definition
 add 5ml of 50X TBE and 45mL of diH2O
Term
 you have a 50X TBE stock solution and you need 50mL of 15X TBE
Definition
 add 15ml of 50X TBE and 35mL of diH2O
Term
 you have a 50X TBE stock solution and you need 50mL of 25X TBE
Definition
 add 25mL of 50X TBE and 25mL of diH2O
Term
 how much solute is required to prepare a 100mL solution of NaCl 2.5M (MW = 58.44 g/mol)
Definition
 g = MW x L x M Weight out 14.16g NaCl. Add 100mL diH2O, Stir solution until blended
Term
 how would you make 300mL of a 0.8M solution of tris buffer (MW = 121.1 g/mol)
Definition
 g = MW x L x Mweight out 29.06g of tris. add to a 500mL flask. add diH20 until you reach 300mL and blend solution
Term
 You need 10% chelex in your lysis buffer, total volume is 1L how much of chelex would you have to add?
Definition
 % = g/mL x = 100g of chelex
Term
 need an 0.8% agarose gel, stock solution is 50X TAE you want 1X TAE, stock EtBr is 10mg/ml but you want 0.5 microgram/ml. you need 80mL total to form the gel.
Definition
 buffer = v1c1=v2c2 = 1.5 mL 50X TAEagarose = g/mL = x/mL = 0.64g agarose EtBr = c1v1 = c2v2 = 0.004 mL = 4 microliters EtBr
Term
 You need 25 mL of a 1:1000 dilution of primary antibody in blocking solution
Definition
 multiply amount needed by dilution factor (1/1000) = 25 microliters 25 microliters of primary antibody was added to 25mL of blocking solution and incubate
Term
 You need 25 mL of a 2:1000 dilution of secondary antibody in blocking solution
Definition
 25 mL x 2/1000 = 50/1000 = 0.05 mL = 50 microliters 50 microliters of secondary antibody was added to 25 mL of blocking solution and incubated
Term
 What is the range of the P-1000
Definition
 200-1000 micro liters
Term
 What is the range of the P-10
Definition
 1-10 micro liters
Term
 You have a 0.25 M solution of Na2EDTA on the shelf. You want to make 100ml of a 1mM solution for use in an experiment. How would you dilute the stock?
Definition
 v1c1 = v2c2 = x 250 = 100 (1) = 0.40mL withdraw 0.40mL of the 0.25M solution of Na2EDTA. Add to flask. add diH20 until solution reaches 100mL in the flask
Term
 How many grams of NaCl would you need to make a 500mL of a 4M NaCl solution?
Definition
 grams/molecular weight / volume = molarity grams/58.44 / 0.5L = 4M grams = 116.88g place a dish on a balance. tare the scale. weight out 116.88g of NaCl onto the dish. add to flask. add dih20 until solution reaches 500mL in the flask
Term
 We have 38% stock acrylamide solution and 2% bis-acrylamide. How many grams of each reagent would you need to make up a 200mL solution?
Definition
 38g x 2 = 76g of acrylamide. 2g x 2 = 4g bis-acrylamide. (x 2 because need 200mL) place a dish on a scale. tare the scale. weight out 76g acrylamide. add to flask. add another dish and tare the scale. weight out 4g of bis-acrylamide. add to flash. add buffer until you reach 200mL in the flask to make a 200mL stock solution
Term
 you need to make a 10% acrylamide gel that requires 80mL total gel solution. your stock acrylamide is 40%. how much of the stock acrylamide would you use and how much buffer?
Definition
 v1c1=c2c2, 20mLwithdraw 20mL of the 40% stock acrylamide. add to flask. 80-20 = 60mL, 60mL buffer to the 20mL of stock acrylamide until you reach 80mL (final volume).
Term
 How much stock acrylamide would you need to make an 8% gel? from 40% stock
Definition
 v1c1=v2c2 = 16mLwithdraw 16mL of the 40% stock acrylamide. add to flash. 80-16 = 64mL, add 64 mL to the 16mL of stock acrylamide until you reach 80mL
Term
 you want to make up 250uL mixture of 4 dNTPs, each a final concentration of 1mM. The stock concentration of the individual dNTPs is 10mM. How would you prepare the mixture in solution?
Definition
 v1c1=v2c2, 25uL x 4 = 100uL total, then add 150uL to get to 250uL
Term
 How would you prepare 500mL of a 10X TBE solution (Tris-Boric acid-Na2EDTA). 10X final concentrations: 1.0 tris (MW=121), 0.89M boric acid (mw=61.8), 0.01M Na2EDTA (mw= 372)
Definition
 (grams/mw)/vol = M, g = M (mw)(v)tris = M mw L = 60.5gboric acid = 27.5gNa2EDTA = 1.86g add 60.5g of tris, 27.5g of boric acid, 1.86g of na2EDTA to a large beaker. Add diH20 until you reach 500mL. Stir solution to mix
Term
 prepare 200mL of a 0.25M KCl solution. you have 2M KCl stock.
Definition
 v1c1=v2c2= 25mL, add 25mL of 2M KCl stock solution to a flask. Add dih20 until the total volume reaches 200mL
Term
 40mL of a 1.5% agarose gel in buffer?
Definition
Term
 How would you prepare 200mL of a stock 10% SDS solution in water?
Definition
Term
 PCR master mix is 24uL and you add 1uL of the primer set, stock concentration is 10uM. What is the final concentration of the primers in the master mix?
Definition
 v1c1=v2c2= 0.4uM Final concentration of the primers in the master mix is 0.4uM
Term
 concentration of protein sample is 35.8mg/ml. want to load 100ug of protein on a 12% poly-acrylamide SDS gel, how much volume of protein sample would you mix with 2X loading solution to achieve 100ug?
Definition
 35.8mg=358000ug and 1ml=1000uL35800/1000 = 100/x x=2.8ul of protein sample is mixed with the loading solution
Term
 1 L =
Definition
 1000 mL
Term
 1 mL =
Definition
 1000 uL
Term
 1 uL =
Definition
 0.001 mL
Term
 range of the P-2
Definition
 0.2-2uL
Term
 range of p-10
Definition
 0.5-10uL
Term
 range of p-20
Definition
 2-20uL
Term
 range of p-200
Definition
 20-200uL
Term
 range of p-1000
Definition
 200-1000uL
Term
 2.5 uL on P-10
Definition
 025
Term
 15.5 uL on P-20
Definition
 155
Term
 160 uL on P-200
Definition
 160
Term
 1 mL on P-1000
Definition
 100
Term
 6.5 uL on P-10
Definition
 0650
Term
 17.8 uL on P-20
Definition
 178
Term
 150 uL on P-200
Definition
 150
Term
 670 uL or 0.67 mL on P-1000
Definition
 0670
Term
 Molarity =
Definition
 Moles of solute/L of solution
Term
 1 M =
Definition
 1 g mw of solute per liter of solution
Term
 if a 1% gel is 1g agarose per 100mL of buffer, how many grams of agarose will you need to make a small agarose?
Definition
 1g/100ml = x/50ml, x= 50x1/100 = 0.50g of agarose
Term
 You have 10X stock solution of TAE buffer. you need 100mL of 1X TAE
Definition
 v1c1=v2c2, 1mL of 10X TAE to 99mL of diH20
Term
 you want to make a 1% agarose gel and we need 50mL total to make a small gel
Definition
 1g/100ml = x/50ml = 0.5gadd 0.5g of agarose to a 250mL flash add 1X TAE until you reach 50mL
Term
 EtBr stock is 10mg/ml and you need 5ug/ml
Definition
 v1c1=v2c2, 2.5uL of EtBr to gel solution
Term
 final concentration of Taq polymerase is to be 0.01 units/uL in a 50uL PCR. If the enzyme supplied if 5 units/uL, how much enzyme would you add to the reaction?
Definition
 v1c1=v2c2, 0.1 uL
Term
 SSC is a buffer in blot NP-40 is a detergent, you need 300mL of 0.2% NP-40 in 2X SSC. Stock for NP-40 is 100%, how much NP-40 do you need to make this solution?
Definition
 v1c1=v2c2, 0.6 mL
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