Term
A casade of 8 a like amp. The 1st amp. has an input of 8dBmV and a NF of 12dB. What the the EOL C/N?
a. 59.2
b. 61.3
c. 55.2
d. 46.2 |
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Definition
d. 46.2
8input 12
L1+59.2 - NF=C/Nt
C/Nt= C/N1 - 10log(#)= 46.2
55.2 8amp. |
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Term
You have a cascade of 18 alike amplifiers. the 1st amp. in the cascade has a 10 dBmV input and has an NF of 14dB. What will be the EOL C/N of the cascade?
a. 41 dB
b. 42.65 dB
c. 43 dB
d. 42.85 dB |
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Definition
b. 42.65 dB
input + 59.2 - NF =
ans - 10log(#) = |
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Term
Your are called out to an escalated poor reception problem after the 8th amplifier in cascade. You take a quick carrier to noise measurement with your meter and you read 42 dB of C/N on ch 70. The week before you took readings at the output of the FNB for C/N and it was 57dB. What should the carrier to noise actually be at this amplifier?
a. 44 dB b. 45 bB c. 46 dB d. 48 dB |
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Definition
d. 48 dB
57-10log(8) =47.9691
C/N - 10log(#)= |
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Term
You are checking the light at the nodes receiver and 1VDC. What is the equal to dBm?
a. 1 dBm
b. 2 dBm
c. 0 dBm
d. .5 dBm |
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Definition
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Term
While measuring 1310nm light hitting an optical receiver in the node with you VOM you must be with-in what voltage DC range?
a. -5 to 3 VDC
b. -10 to 10 VDC
c. .5 to 2 VDC
d. .3 to 2 VDC |
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Definition
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Term
The input of an amplifier with an 8dB Noise Figure is connected to a 75-ohm carrier generator that adds no noise of its own. The generator is adjusted to deliver a +10 dBmV level to the amplifier. What is the C/N ratio at the output of the amplifier.
a. 50 dB
b. 69 dB
c. 61 dB
d. 67 dB
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Definition
c. 61 dB
10+59.2-8=61.2 dB
input+59.2-NF=? |
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