Term
| 196 Newtons (The formula is an application of F = m*a, where F = force, m = mass, and a = acceleration due to gravity. Here m = 20 and a = 9.8, so F = 20*9.8 = 196.) |
|
Definition
| What is the weight in Newtons of a 20-kg mass? |
|
|
Term
| 144 Newton-seconds (The formula is p = m*v where p is momentum, m = mass, and v = velocity; m = 24 and v = 6, so p = 24*6 = 144.) |
|
Definition
| What is the momentum in Newton-seconds for a mass of 24 kg moving at a speed of 6 meters per second? |
|
|
Term
| 880 foot-pounds (The formula is either PE = m*g*h or PE = w*h, where m = mass, g = acceleration due to gravity, h = height, and w = weight; w = 110 and h = 8, so PE = 110*8 = 880.) |
|
Definition
| An object with weight of 110 pounds is suspended 8 feet above the ground. What is the potential energy of the weight? |
|
|
Term
| 130 Joules (The formula is W = F*d, where W = work, F = force, and d = distance; F = 650 and d = 0.2, so W = 650*0.2 = 130.) |
|
Definition
| What work is needed to move a mass of 650 Newtons a distance of 0.2 meters? |
|
|
Term
| 15,000 Joules (The formula is W = P*t, where W = work, P = power, and t = time, but the time is in seconds, so P = 250 and t = 60, and therefore W = 250*60 = 15000.) |
|
Definition
| What work is done when a power of 250 watts is applied for 1 minute? |
|
|
Term
| 204 volts (The formula is V = I*R, where V = voltage, I = current, and R = resistance; I = 0.52 and R = 400, so V = 0.52*400 = 204.) |
|
Definition
| What is the voltage in a circuit with 0.52 ampere of current flowing with a resistance of 400 ohms? |
|
|
Term
| 5.1 Joules (The formula is T = F*d, where F is the force and d is the distance; F = 17 and d = 0.3 meters, so T = 17*0.3 = 5.1.) |
|
Definition
| What torque is applied to a screw if someone with a wrench applies a force of 17 Newtons at a distance of 30 centimeters from the screw? |
|
|
Term
| 492 Newtons (The formula is Hooke's Law F = k*x, where k = spring constant and x = distance stretched or compressed beyond natural length; k = 82 and x = 6, so F = 82*6 = 492.) |
|
Definition
| A spring with a spring constant of 82 Newtons per meter is stretched to a length of 6 meters beyond its natural length. What force is applied? |
|
|
